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const 成员变量的初始化
const的成员变量只能在类的构造函数初始化，如下编译报错

//const.h#include<iostream>class cconst{public:    cconst();    void

print()    {        std::cout<<"----"<

const int cs;};
//const.cpp#include"const.h"cconst::cconst(){}int main(int argc, char*

argv[]){    cconst* a = new cconst();    a->print();    return 0;}

编译报错error c2758: "cs" : must be initialized in constructor

base/member initializer list

将const.cpp修改为：

#include"const.h"cconst::cconst(){    cs = 0;}int main(int argc, char*

argv[]){    cconst* a = new cconst();    a->print();    return 0;}

仍然报错：

error c2758: "cs" : must be initialized in constructor base/member

initializer list

修改为下面形式后，正常：

#include"const.h"cconst::cconst():cs(0){    //cs = 0;}int main(int argc,

char* argv[]){    cconst* a = new cconst();    a->print();    return 0;}

iostream>

本文来源：http://www.gdgbn.com/jiaocheng/29296/