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这是应为在方法级别的synchronized声明将lock这个类对象的当前实例。所以在synMethord1运行结束unlock之前,当前Java SynDemo对象实例是无法运行synMethord2的。这种方法级别的synchronized声明和以下的做法是等同的:
1.package com.cnblogs.gpcuster;/** * * @author Aaron.Guo * */
2.public class SynDemo { public void synMethord1() {
synchronized (this) { while (true) { try { Thread.sleep(1000);
System.out.println("synMethord1"); } catch (InterruptedException
e) { // TODO Auto-generated catch block
3.e.printStackTrace();
4.}
5.}
6.}
7.}
8.public void synMethord2() { synchronized (this) { while (true)
{ try { Thread.sleep(1000); System.out.println("synMethord2"); }
catch (InterruptedException e) { // TODO Auto-generated catch block
9.e.printStackTrace();
10.}
11.}
12.}
13.}
14.}
运行程序,结果与上次相同。
如果我们希望分别同步2个方法该如何处理?可以参考这个实现:
15.package com.cnblogs.gpcuster;/** * * @author Aaron.Guo * */
16.public class SynDemo { private Object flag1 = new Object();
private Object flag2 = new Object(); public void synMethord1()
{ synchronized (flag1) { while (true) { try { Thread.sleep(1000);
System.out.println("synMethord1"); } catch (Interrupted
Exception e) { // TODO Auto-generated catch block
17.e.printStackTrace();
18.}
19.}
20.}
21.}
22.public void synMethord2() { synchronized (flag2) { while (true)
{ try { Thread.sleep(1000); System.out.println("synMethord2"); }
catch (InterruptedException e) { // TODO Auto-generated catch block
23.e.printStackTrace();
24.}
25.}
26.}
27.}
28.}
运行程序,结果如我们预期:
29.main
30.synMethord2
31.synMethord2
32.main
33.synMethord1
34.main
35.synMethord1
36.synMethord2