【www.gdgbn.com--js教程】
ajax php教程用户无刷新登录实例
<script>
function userlogin(){
var xmlhttp;
var str;
var sendstr="";
try{
xmlhttp=new xmlhttprequest();
}
catch(e){
xmlhttp=new activexobject("microsoft.xmlhttp");
}
xmlhttp.onreadystatechange=function(){
if (xmlhttp.readystate==4){
if (xmlhttp.status==200){
str = xmlhttp.responsetext;
document.getelementbyid("userlogin").innerhtml=str;
}else{
alert("系统错误,如有疑问,请与管理员联系!"+xmlhttp.status);
}
}
}
xmlhttp.open("post","config/userlogin.php",true);
xmlhttp.setrequestheader("content-type","application/x-www-form-urlencoded");
xmlhttp.send(sendstr);
}
</script>
userlogin.php文件
$uid = $_post["uname"];
$pwd = $_post["upwd"];
$sql ="select * from tabname where uid="$uid" and pwd="$pwd"";
$query = mysql教程_query( $sql );
if( mysql_num_rows( $query ) )
{
echo "登录成功";
}
else
{
echo "用户名或密码不正确!";
}
?>